Solving Systems of Equations

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Taught by MrRutter

Currently 4.0/5 Stars.

7045 views | 2 ratings

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Part of video series

Previous | Solving Systems of Equations

Meets NCTM Standards:

2b
2c
3b

Lesson Summary:

In this lesson, you will learn how to solve a system of equations using both substitution and elimination. Substitution involves replacing a variable with its equivalent expression, while in elimination, you add or subtract the equations to get one variable eliminated. By applying these methods to different equations with different variables, you can solve for unknown variables and obtain solutions.

Lesson Description:

Learn what it means to solve a system of equations using substitution and elimination.

Questions answered by this video:

How do you solve a system of equations using substitution?
What is substitution in Algebra?
How do you solve the system of equations x + 4y = 26 and x - 5y = -10 using substitution?
How do you solve a system of equations using elimination?
How do you solve the system of equations 3x - y = 7 and x + 4y = 11 using elimination?
How do you get a variable to cancel out when solving a system of equations?
When you find the value of one variable in a system of equations, how do you find the value of the other variable?

Staff Review
- Currently 4.0/5 Stars.
This lesson explains the concept of substitution in Algebra and then uses this concept to solve an equation for a variable and substitute that expression into the other equation to solve. Then, the process of solving using elimination is explained and shown for a different example problem.

How staff ratings work
contrell81
- Currently 5.0/5 Stars.
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