# Solving Systems of Equations by substitution - part 2

Taught by YourMathGal
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Lesson Description:

This is part 2 of how to solve a system of equations using the substitution method. It covers special cases--a dependent system when the 2 equations are the same, and therefore the solution is infinitely many ordered pairs. The other is an inconsistent system, so there is no solution.

More free YouTube videos by Julie Harland are organized at http://yourmathgal.com

• How do you solve systems of equations with substitution?
• How do you solve the system of equations 2y = x + 2 and 6x - 12y = 0?
• How do you solve for two variables with two equations?
• How do you solve a system of equations using substitution when no variable is by itself?
• What happens in a system of equations when you get a false statement like -12 = 0 or 1 = 0?
• What does it mean for a system of equations to be inconsistent?
• What is the answer or solution to an inconsistent system of equations?
• How do you solve the system of equations 1/4x - 2y = 1 and x - 8y = 4 by substitution?
• What happens in a system of equations when you get a true statement like 0 = 0 or 1 = 1?
• What does it mean for a system of equations to be dependent?
• What is the answer or solution to a dependent system of equations?
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• Currently 3.0/5 Stars.
This lesson goes through some special cases of systems of equations. In the first example, you end up getting a false statement, which means the system is inconsistent and there is no solution. In the second example, you get a true statement, which means the system is dependent and there are infinitely many solutions. Both examples are done in great detail and explained very well. The video is very similar to the previous system of equations video, and is very well done.