# Percent Mixture Problem #3

Taught by YourMathGal
• Currently 4.0/5 Stars.
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Part of video series
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Lesson Summary:

In this lesson, the instructor uses a visual representation to explain how to solve a percent mixture problem using one variable. The problem involves combining five pounds of candy that is 20% chocolate with a candy that is 40% chocolate to get a candy that is 25% chocolate. The instructor presents two methods of solving the problem, one using decimals and the other using fractions, and then demonstrates how to check the answer. By the end of the lesson, viewers will have a solid understanding of how to approach and solve this type of problem.

Lesson Description:

Explains using picture how to solve this percent mixture problem using one variable: Five pounds of candy that is 20% chocolate is combined with a candy that is 40% chocolate. How many pounds of the candy that is 40% chocolate should be used to get a candy that is 25% chocolate?

More free YouTube videos by Julie Harland are organized at http://yourmathgal.com

• How do you solve percent mixture problems with one variable?
• How do you write and solve an equation for a percent mixture problem?
• How do you draw a picture of a percent mixture problem in Algebra?
• How can you check to make sure that your solution to a percent mixture word problem is correct?
• If five pounds of candy that is 20% chocolate is combined with a candy that is 40% chocolate, how many pounds of the candy that is 40% chocolate should be used to get a candy that is 25% chocolate?
• How do you solve .20(5) + .40x = .25(x + 5)?
• How do you solve an equation with decimals by first clearing out all of the decimals?
• What happens if you get a fraction in a word problem?
• #### Staff Review

• Currently 4.0/5 Stars.
This percent mixture word problem shows another possible scenario in which you have to find out a missing amount. Each step and part is explained step by step with pictures drawn and equations written and solved. The answer is also checked to be sure it is correct. This lesson answers a very commonly difficult problem for students in a very clear way.