Synthetic Division Part 5

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Taught by YourMathGal
  • Currently 4.0/5 Stars.
5139 views | 1 rating
Part of video series
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Lesson Summary:

This lesson on synthetic division teaches how to divide a polynomial by a linear binomial using synthetic division, with an added twist when the coefficient of x in the linear binomial is not 1. The video demonstrates how to solve this problem and check the work, ensuring that each coefficient in the quotient is divided by the coefficient of x at the end of the problem. The lesson concludes with tips on how to recognize different formulations of division problems and presents a comprehensive approach to solving such problems.

Lesson Description:

This video shows how to divide a polynomial by a linear binomial using synthetic division. Checking work is also shown. Shows how to use synthetic division when coefficient of x in linear binomial is not 1.

More free YouTube videos by Julie Harland are organized at http://yourmathgal.com

Questions answered by this video:
  • How do you divide a polynomial by a binomial when the binomial does not have a leading coefficient of 1?
  • How do you divide (2x^2 - 9x + 8)/(2x - 3) using synthetic division?
  • How do you know what number goes in the box in a synthetic division problem?
  • What do you have to do at the end of a synthetic division problem if the leading coefficient of the binomial is not 1?
  • How can you check your answer to a polynomial division problem?
  • Staff Review

    • Currently 4.0/5 Stars.
    This lesson take synthetic division a step further -- by dividing a polynomial by a binomial where the binomial does not have a leading coefficient of 1. The first step is to figure out what goes in the box to perform the synthetic division, and at the end of the problem, you have to divide the coefficients by the leading coefficient of the binomial.