# Elementary Algebra Review Part 23

Taught by YourMathGal
• Currently 4.0/5 Stars.
6993 views | 1 rating
Part of video series
Lesson Summary:

In this lesson on elementary algebra, students learn how to write word statements as variable equations and solve them. They also learn how to substitute values into variables in formulas and solve for an unknown variable. The lesson includes examples of solving for the measures of angles in a triangle and solving formulas for the area of a trapezoid, perimeter of a rectangle, and circumference of a circle. The instructor uses clear explanations and step-by-step examples to make the material accessible to learners of all levels.

Lesson Description:

Writing word statements as variable equations and solving, and substituting values into variables in formulas and solving for an unknown variable.

More free YouTube videos by Julie Harland are organized at http://yourmathgal.com

• How do you write word statements as variable equations and solve and check them?
• How do you solve a word problem using algebra?
• What does it mean to define a variable?
• How do you translate words into Algebra?
• How do you check your solution to a word problem?
• If the sum of the measures of the angles in a triangle is 180 degrees, two angles have the same measure, and the third angle is 20 degrees less than the sum of the two smaller angles, what is the measure of the three angles?
• If x + x + 2x - 20 = 180, what is x?
• How do you substitute given values into a formula and solve for the unknown variable?
• If A = 1/2h(B + b) and A = 52, B = 8, b = 5, what does h equal?
• How do you solve a formula for a variable?
• If P = 2L + 2W, and P = 96 and L = 26, what does W equal?
• How do you solve for r in C = 2*pi*r?
• #### Staff Review

• Currently 4.0/5 Stars.
This lesson shows one more example of taking an angle measure word statement, turns it into an algebraic equation, solves, and checks. This very common problem is explained very well. Then, some values are substituted into formulas, and unknown variables are solved for.