Quadratic in Form Equation 1

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Taught by YourMathGal
  • Currently 4.0/5 Stars.
6721 views | 1 rating
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Lesson Summary:

This lesson teaches how to solve an equation that is quadratic in form by substituting a variable for the middle term of the equation. By factoring the resulting quadratic equation, it is possible to solve for the variable and then substitute the value obtained back into the original equation. The highest degree of the polynomial determines how many solutions there might be. It is essential to check all the solutions in the original equation to verify their validity. Different methods can be used to solve these types of equations, but the use of substitution is one of the most common.

Lesson Description:

Example of solving an Equation that is Quadratic in form.

More free YouTube videos by Julie Harland are organized at http://yourmathgal.com

Questions answered by this video:
  • How do you solve x^4 - 13x^2 + 36 = 0?
  • How do you solve an equation with an x^4 in it?
  • How do you solve an equation in the form au^2 + bu + c = 0?
  • What is u substitution?
  • How can an equation have four solutions?
  • How do you know how many solutions you can have in an equation?
  • How do you check your solutions to an equation?
  • How do you factor a 4th degree polynomial?
  • How do you factor x^4 - 13x^2 + 36 = 0?
  • Staff Review

    • Currently 4.0/5 Stars.
    This lesson explains how to set up and solve equations that look and act like quadratic equations but have a higher exponent than 2. The substitution and all steps involved in solving are shown and explained. Also, you will learn to recognize situations where this method applies, such as ay^6 + by^3 + c = 0 or a(x + 1)^2 + b(x + 1) + c = 0. It is also important to check your solutions.