Parabolas 9

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Taught by YourMathGal
  • Currently 4.0/5 Stars.
6925 views | 1 rating
Part of video series
Meets NCTM Standards:
Lesson Summary:

In this lesson on Parabolas 9, the instructor teaches how to graph the function f(x) = -2x^2 + 6x and find the axis of symmetry and vertex point. The formula x = -b/2a is used to find the axis of symmetry which is x = 3/2, and plugging this value back into the function gives the vertex point of (3/2, 9/2). The lesson emphasizes the importance of simplifying fractions and provides alternative ways to express the vertex point.

Lesson Description:

Graphing Parabolas Part 9;

More free YouTube videos by Julie Harland are organized at http://yourmathgal.com

Questions answered by this video:
  • How do you graph a parabola in standard form?
  • How do you find the vertex and axis of symmetry for a parabola?
  • How do you know whether a parabola opens up or down?
  • How do you know whether the graph of a parabola will be steep or wide?
  • How do you find the x-intercepts and y-intercept of a parabola?
  • How do you find the domain and range of a parabola?
  • How do you find the max / min of a parabola?
  • How do you graph f(x) = -2x^2 + 6x?
  • What is the equation for the vertex and axis of symmetry of a parabola?
  • How do you convert a quadratic equation from standard form to vertex form?
  • Staff Review

    • Currently 4.0/5 Stars.
    This lesson extends the ideas learned from the previous lesson and goes through another example of finding all of the characteristics and important values for a parabola in standard form. All steps needed to find these values are shown and explained. The equation is also graphed. Unfortunately, the sound cuts out at the 3-minute mark, but all work is still shown.