Parabolas 9
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Lesson Summary:
In this lesson on Parabolas 9, the instructor teaches how to graph the function f(x) = -2x^2 + 6x and find the axis of symmetry and vertex point. The formula x = -b/2a is used to find the axis of symmetry which is x = 3/2, and plugging this value back into the function gives the vertex point of (3/2, 9/2). The lesson emphasizes the importance of simplifying fractions and provides alternative ways to express the vertex point.
Lesson Description:
Graphing Parabolas Part 9;
More free YouTube videos by Julie Harland are organized at http://yourmathgal.com
Questions answered by this video:
- How do you graph a parabola in standard form?
- How do you find the vertex and axis of symmetry for a parabola?
- How do you know whether a parabola opens up or down?
- How do you know whether the graph of a parabola will be steep or wide?
- How do you find the x-intercepts and y-intercept of a parabola?
- How do you find the domain and range of a parabola?
- How do you find the max / min of a parabola?
- How do you graph f(x) = -2x^2 + 6x?
- What is the equation for the vertex and axis of symmetry of a parabola?
- How do you convert a quadratic equation from standard form to vertex form?
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Staff Review
This lesson extends the ideas learned from the previous lesson and goes through another example of finding all of the characteristics and important values for a parabola in standard form. All steps needed to find these values are shown and explained. The equation is also graphed. Unfortunately, the sound cuts out at the 3-minute mark, but all work is still shown.
