Percent Mixture Problem #4

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Taught by YourMathGal
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Part of video series
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Lesson Summary:

In this lesson, we learn how to solve percent mixture problems using one variable by figuring out how much water should be added to a container of juice that is 70% juice to get a diluted mixture that is only 60% juice. By setting up an equation that represents the amount of pure juice in each container, we can solve for the variable, which in this case is the amount of water to be added. The solution is checked to make sure the final amount of pure juice is the same in both containers, and we discover that adding 5 cups of water is the solution to the given problem.

Lesson Description:

Explains using picture how to solve this percent mixture problem using one variable: How much water should be added to 30 cups of juice that is 70% juice to get a diluted mixture that is only 60% juice?

More free YouTube videos by Julie Harland are organized at http://yourmathgal.com

Questions answered by this video:
  • How do you solve percent mixture problems with one variable?
  • How do you write and solve an equation for a percent mixture problem?
  • How do you draw a picture of a percent mixture problem in Algebra?
  • How can you check to make sure that your solution to a percent mixture word problem is correct?
  • How much water should be added to 30 cups of juice that is 70% juice to get a diluted mixture that is only 60% juice?
  • How do you solve the equation 0x + .7(30) = .6(x + 30)?
  • How do you solve an equation with decimals by first clearing out all of the decimals?
  • Staff Review

    • Currently 4.0/5 Stars.
    This final installment of this series on percent mixture word problems is a very real-world example of diluting a strong liquid with water. Each step is explained clearly as this problem is solved. This is a great last video in this series.