Percent Mixture Problem #4

In this lesson, we learn how to solve percent mixture problems using one variable by figuring out how much water should be added to a container of juice that is 70% juice to get a diluted mixture that is only 60% juice. By setting up an equation that represents the amount of pure juice in each container, we can solve for the variable, which in this case is the amount of water to be added. The solution is checked to make sure the final amount of pure juice is the same in both containers, and we discover that adding 5 cups of water is the solution to the given problem.

Explains using picture how to solve this percent mixture problem using one variable: How much water should be added to 30 cups of juice that is 70% juice to get a diluted mixture that is only 60% juice?

• How do you solve percent mixture problems with one variable?
• How do you write and solve an equation for a percent mixture problem?
• How do you draw a picture of a percent mixture problem in Algebra?
• How can you check to make sure that your solution to a percent mixture word problem is correct?
• How much water should be added to 30 cups of juice that is 70% juice to get a diluted mixture that is only 60% juice?
• How do you solve the equation 0x + .7(30) = .6(x + 30)?
• How do you solve an equation with decimals by first clearing out all of the decimals?