Solving a System of Equations by Substitution - part 1

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Taught by YourMathGal
  • Currently 4.0/5 Stars.
11438 views | 2 ratings
Part of video series
Meets NCTM Standards:
Lesson Summary:

In this lesson, you will learn how to solve a system of equations by substitution method as demonstrated with two examples. If one of the equations is solved for x or y, that value can be substituted into the other equation to create an equation with one variable. The first example shows how to solve a system of equations with y already solved for. In the second example, the instructor explains how to select the easiest variable to solve for by identifying which one has a coefficient of one or negative one.

Lesson Description:

This is part 1 of how to solve a system of equations using the substitution method. The first system solved is 2x - y = -5 and y = x + 4. The second system solved is 3x + y = -14 and 4x + 3y = -22.

More free YouTube videos by Julie Harland are organized at http://yourmathgal.com

Questions answered by this video:
  • How do you solve systems of equations using substitution?
  • What is the substitution method for solving systems of equations?
  • How do you solve the system of equations 2x - y = -5 and y = x + 4?
  • How do you know when to use the substitution method?
  • How can you check your solution in a systems of equations problem?
  • How do you solve the system of equations 3x + y = -14 and 4x + 3y = -22?
  • How do you solve a system of equations using substitution when no variable is by itself?
  • How do you solve for two variables with two equations?
  • Staff Review

    • Currently 3.0/5 Stars.
    This video does a really good job of explaining when to use the substitution method to solve systems of equations, how it works, and what it looks like to actually solve. Each step is shown and explained in detail. This is a must-see for anyone learning how to solve systems of equations using substitution.